Question #142936
A 10 kg ball traveling 2 m/s collides elastically with a 2 kg ball traveling 4 m/s. After the collision the 2 kg ball rolls away at 6m/s. Find the velocity of the 10 kg ball.

m1v1 + m2v2 before= m1v1 + m2v2 after
1
Expert's answer
2020-11-10T07:02:40-0500
m1v1m2v2=m1v1+m2v210(2)2(4)=10v1+2(6)v1=0msm_1v_1 -m_2v_2=m_1v_1'+ m_2v_2'\\10(2)-2(4)=10v_1'+2(6)\\v_1'=0\frac{m}{s}


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