Answer to Question #140657 in Field Theory for Sneha

Question

Write down formula for maximum height and maximum range of projectile motion.

Answer 1

Solution

In case of maximum height projection angle is 90^°

So Maximum height can be expressed by following formula

$H_{max}=\frac {v^2}{2g}$

Where v is projection velocity.

Now for maximum range angle must be 45^° so

Maximum

$R_{max}=\frac{v^2}{g}$