Answer to Question #129063 in Field Theory for Sharon

Question

a proton (charge +e = ) moves in a straight line from point a to point b
inside a linear accelerator , a total distance d= 0.50m. the electric field is uniform along the line with
magnitude E = . In the direction from a to b determine
i. the force on the proton?
ii. the work done on it by the field?
iii. the potential difference ?

Answer 1

i)

$$F=qE=(1.6\cdot10^{-19})(1.5\cdot10^{7})=2.4\cdot10^{-12}\ N$$

ii)

$$W=qEd=(1.6\cdot10^{-19})(1.5\cdot10^{7})(0.5)\\=1.2\cdot10^{-12}\ J$$

iii)

$$U=Ed=(1.5\cdot10^{7})(0.5)=0.75\cdot10^{7}\ V$$