Answer to Question #125810 in Field Theory for Gabby Thayer

Question #125810
Two 15 nC charges are at (0, -10 cm) and (0, 10 cm) on the y-axis as shown. What is the strength of the electric field at a point 50 cm away on the x-axis?
1
Expert's answer
2020-07-10T10:25:08-0400



The total strength of the electric field


E=E1cosθ+E2cosθ=2E1cosθE=E_1\cos\theta+E_2\cos\theta=2E_1\cos\thetacosθ=50502+102=526=0.98\cos\theta=\frac{50}{\sqrt{50^2+10^2}}=\frac{5}{\sqrt{26}}=0.98E1=kqr2=9×10915×1090.52+0.12=519N/CE_1=k\frac{q}{r^2}=9\times 10^9\frac{15\times 10^{-9}}{0.5^2+0.1^2}=519\:\rm N/CE=2×519×0.98=1018N/CE=2\times 519\times 0.98=1018\:\rm N/C

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