Question #124916
A thin spherical shell of metal has a radius of 0.25m and carries charge of 0.2 microcoloumb . calculate the electric intensity just outside the shell.
1
Expert's answer
2020-07-03T10:04:43-0400

Apply the Gauss's law we get


ϕ=SEdA=qenclosedϵ0\phi=\oiint_{S}\overrightarrow{E}\cdot d\overrightarrow{A}=\frac{q_{enclosed}}{\epsilon_0}

Thus, in this case as spherical shell is symmetric, thus

ESdA=2×107ϵ0    E(4πr2)=2×107ϵ0    E=14πϵ02×1070.252=9×109×2×107/0.252=28800N/CE\oiint_{S}dA=\dfrac{2\times 10^{-7}}{\epsilon_0}\\ \implies E(4\pi r^2)=\dfrac{2\times 10^{-7}}{\epsilon_0}\\\implies E=\dfrac{1}{4\pi\epsilon_0}\dfrac{2\times 10^{-7}}{0.25^2}=9\times 10^9\times 2 \times 10^{-7}/0.25^2=28800N/C


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