Answer to Question #115384 in Field Theory for 250300183747

Question #115384

Two long parallel wires are 10 cm apart and carry currents of 6 A and 4 A. what is the field B at 4 A carrying wire due to 6 A wire.

Expert's answer

"B=\\frac{\\mu_oI}{2\\pi R}=\\frac{4\\pi\\times10^{-7}\\times6}{2\\pi\\times0.1}=12\\times10^{-6}H"

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