Question #112424
An object slides down an inclined plane from an initial height of 30 meters.Its velocity at the foot of the plane is 20m/s.
The percentage of its initial potential energy which is deposited as heat is?
1
Expert's answer
2020-04-27T10:00:19-0400

The initial potential energy

PEi=mghPE_i=mgh

The final kinetic energy

KEf=mv22KE_f =\frac{mv^2}{2}

The heat losses

Q=PEiKEf=mgh(1v22gh)Q=PE_i-KE_f=mgh\left(1-\frac{v^2}{2gh}\right)

Hence, the percentage of its initial potential energy which is deposited as heat

QPEi=1v22gh=12022×9.8×30=0.32=32%\frac{Q}{PE_i}=1-\frac{v^2}{2gh}=1-\frac{20^2}{2\times 9.8\times 30}=0.32=32\%

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