Answer to Question #112398 in Field Theory for Rishabh

Question #112398
The expression of the magnetic field associated with an electromagnetic wave in 'vacuum is given by
B = (100D) ysin(2 x103t +k
Determine the wave number, frequency and the direction of propagation of the wave, " aand the magnitude and direction of the electric field associated with it.
1
Expert's answer
2020-04-27T10:12:26-0400

The wave number is


k=ωc=20003108=6.67106m1k=\frac{\omega }{c}=\frac{2000}{3\cdot10^8}=6.67\cdot10^{-6}m^{-1}


f=20002π=318.3 Hzf=\frac{2000}{2\pi}=318.3\ HzE=Bc=(100)(3108)=31010VmE=Bc=(100)(3\cdot10^8)=3\cdot10^{10}\frac{V}{m}


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