Answer to Question #100378 in Field Theory for Derickson

Question #100378
A helical spring is extended by a force which increase uniformally from 0 to 600 newtons. The corresponding extension of the spring is 200mm. What is the total work done?
1
Expert's answer
2019-12-13T10:09:37-0500

"W=0.5Fx"

"W=0.5(600)(0.2)=60\\ J"


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