Question

Calculate the velocity of water in a pipe of cross sectional area 0.02sqaure meters which delivers 115 liters of water per second.

Answer 1

The flux of water having velocity $v$ through pipe of cross sectional area $S$ in time $t$ is $I = S v t$.

Hence, the velocity is $v = \frac{I}{S t} = \frac{115 \cdot 10^{-3} m^3}{0.02 m^2 \cdot 1 s} = 5.75 \frac{m}{s}$.