The flux of water having velocity "v" through pipe of cross sectional area "S" in time "t" is "I = S v t".
Hence, the velocity is "v = \\frac{I}{S t} = \\frac{115 \\cdot 10^{-3} m^3}{0.02 m^2 \\cdot 1 s} = 5.75 \\frac{m}{s}".
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