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Consider a square loop of wire, of side length l, lying in the xy−plane as shown in
figure. Suppose a particle of charge q is moving with velocity v, where v << c, in the
xz−plane at a constant distance z0 from xy−plane (Assume the particle is moving
in the positive x−direction). Suppose the particle crosses the z−axis at t=0. Give
the induced emf in the loop as a function of time.

For discharging process

R=10KiloOHM,V=470microF, E=12V.

A)What value will be the voltage across the capacitor 2 time constant

B)what value will be the voltage across after 6 seconds.

C)when the capacitor will be fully charged

D)when will the current through the circuit be reduced by 25%


Explain why the path has this general shape and why it is repetitive.



A parallel-plate capacitor of a plate area A and plate separation d. The left half

of the gap is filled with a material with dielectric constant κ1; the top of the right half is filled with

material of dielectric constant κ2; the bottom of the right half is filled material of dielectric constant

κ3. What is the capacitance C?


A parallel plate capacitor has the space between the plates filled with two slabs of dielectric, one with constant κ1 and one with constant κ2. Each slab has thickness d/2, where d is the plate separation. Show that the capacitance is C = 2ε0A /d (κ1κ2/κ1 + κ2)


Consider three identical ideal capacitors. The first capacitor is charged to a voltage V0 and then disconnected from the battery. The other two capacitors, initially uncharged and connected in series, are then connected across the first capacitor. What is the final voltage on the first capacitor?


A parallel plate air capacitor is made by using two plates 16cm square, spaced 4.7mm apart. It isconnected to a 12.0V battery. (a) What is the capacitance? (b) What is the charge on each plate? (c)What is the electric field between the plates? (d) What is the energy stored in the capacitor? (e) If the battery is disconnected and then the plates are pulled apart to a separation of 9.4mm, what arethe answers to (a), (b),(c) and (d)?


A parallel-plate capacitor whose capacitance is C = 13.5pF has a potential difference of V = 12.5Vbetween its plates. The charging battery is now disconnected and a porcelain slab with dielectricconstant κ = 6.50 is slipped between the plates. What is the potential energy of the device before andafter the slab is introduced?

A parallel plate capacitor has the space between the plates with two slabs of dielectric, one with dielectric constant κ1 and one with constant κ2. The thickness of each slab is the same as the plate separation d, and each slab fills half of the volume between the plates. Show that the capacitance is C = 0A(κ1 + κ2) 2d


A parallel plate capacitor has the space between the plates filled with two slabs of dielectric, one with constant κ1 and one with constant κ2. Each slab has thickness d/2, where d is the plate separation. Show that the capacitance is C = 20A d  κ1κ2 κ1 + κ2 


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