We have
νmin=20Hz\nu_{min}=20Hzνmin=20Hz
Then the wavelength equivalent to it
λmax=vsoundsνmin=331 m/s20 1/s=16.55m\lambda_{max}=\frac{v_{sounds}}{\nu_{min}} = \frac{331\text{ m/s}}{20\text{ 1/s}}=16.55mλmax=νminvsounds=20 1/s331 m/s=16.55m
organ pipe size is
L=12⋅λmax=12⋅16.55=8.275mL=\frac{1}{2} \cdot \lambda_{max} =\frac{1}{2} \cdot 16.55=8.275mL=21⋅λmax=21⋅16.55=8.275m
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