Field potential from charge A at a given location
ϕA=k⋅raqa
Field potential from charge B at a given location
ϕB=k⋅rbqb
by condition of the problem
ϕA=ϕB
or
k⋅raqa=k⋅rbqb
raqa=rbqb
then
qaqb=rarb=0.190.67=3.53
Answer: 3.53
Comments
Leave a comment