Field potential from charge A at a given location
"\\text{ } \\phi_A=k\\cdot\\frac{q_a}{r_a}"
Field potential from charge B at a given location
"\\text{ } \\phi_B=k\\cdot\\frac{q_b}{r_b}"
by condition of the problem
"\\text{ } \\phi_A=\\phi_B"
or
"k\\cdot\\frac{q_a}{r_a}=k\\cdot\\frac{q_b}{r_b}"
"\\text{ } \\frac{q_a}{r_a}=\\frac{q_b}{r_b}"
then
"\\frac{q_b}{q_a}=\\frac{r_b}{r_a}=\\frac{0.67}{0.19}=3.53"
Answer: 3.53
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