Answer to Question #96622 in Electricity and Magnetism for Antonio Rodriguez

Question #96622
Two charges A and B are fixed in place, at different distances from a certain spot. At this spot the potentials due to the two charges are equal. Charge A is 0.19 m from the spot, while charge B is 0.67 m from it. Find the ratio qB/qA of the charges.
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Expert's answer
2019-10-16T09:38:34-0400

Field potential from charge A at a given location

 ϕA=kqara\text{ } \phi_A=k\cdot\frac{q_a}{r_a}

Field potential from charge B at a given location

 ϕB=kqbrb\text{ } \phi_B=k\cdot\frac{q_b}{r_b}

by condition of the problem

 ϕA=ϕB\text{ } \phi_A=\phi_B

or

kqara=kqbrbk\cdot\frac{q_a}{r_a}=k\cdot\frac{q_b}{r_b}

 qara=qbrb\text{ } \frac{q_a}{r_a}=\frac{q_b}{r_b}

then

qbqa=rbra=0.670.19=3.53\frac{q_b}{q_a}=\frac{r_b}{r_a}=\frac{0.67}{0.19}=3.53

Answer: 3.53


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