Question

Two charges 10C and 50C are separated by r units.What is the force acting on them?

Answer 1

Two charges 10C and 50C are separated by r units. What is the force acting on them? Please explain Solution

This force $(F)$ acting simultaneously on point charges $(q_{1})$ and $(q_{2})$, is given by

$$| \boldsymbol {F} | = k _ {e} \frac {| q _ {1} q _ {2} |}{r ^ {2}}$$

In our case

$$F = k _ {e} \frac {1 0 C 5 0 C}{r ^ {2}} = 5 0 0 \frac {k}{r ^ {2}}$$

$k_{e}$ is a proportionality constant.

$$\begin{array}{l} k _ {\mathrm {e}} = \frac {1}{4 \pi \varepsilon_ {0}} = \frac {c ^ {2} \mu_ {0}}{4 \pi} = c ^ {2} \cdot 1 0 ^ {- 7} \mathrm {H m} ^ {- 1} \\ = 8. 9 8 7 5 5 1 7 8 7 3 6 8 1 7 6 4 \cdot 1 0 ^ {9} \mathrm {N m} ^ {2} \mathrm {C} ^ {- 2} \\ \end{array}$$