Question

Suppose the charge on the electron and proton did not
have the same magnitude but instead differed by one part in 10^10. What would be the net charge on a 1.0 kg of the helium sample

Answer 1

The total number of electrons per He molecule is equal to 2.

The number of moles in 1.0 kg of the helium sample is equal to

$\frac{1000}{4}=250$

The number of molecules of He in sample is equal to

250×6.02×10²³=1.5×10²⁵

The number of electrons in 1 kg of the helium sample is equal to

2×1.5×10²⁵=3×10²⁵

The total charge of those electrons is

3×10²⁵×(-1.6×10^-19)=-4.8×10^-6 C

Answer

-4.8×10^-6 C