The total electric force is given by formula:
Fnet=Fx2+Fy2(1)F_{net} = \sqrt {{F_{x}}^2+{F_{y}}^2} (1)Fnet=Fx2+Fy2(1)
Coulomb law
F=k×q1×q2r2(2)F= k×\frac {q_{1}×q_{2}}{r^2} (2)F=k×r2q1×q2(2)
where k=9×109
Using (2) we get
Fx= 2.4 N (3)
Fy=7.2 N (4)
We put (3) and (4) in (1)
F=7.59 N
tanθ=FyFx(5)\tanθ=\frac {F_{y}}{F_{x}} (5)tanθ=FxFy(5)
We put (3) and (4) in (5)
tanθ=3\tanθ=3tanθ=3
θ=252°
The angle is equal to
360°-252°=108°
Answer
7.59 N
108°
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments