Question #92367
Three charges Q1
= -2μC (0,0)cm, Q2
= 4 μC (0,10)cm
and Q3
= -3 μC (15,0)cm acts on one another. Find the
magnitude of the total electric force and the angle
that the total electric force makes with the positive
x-axis.
1
Expert's answer
2019-08-16T09:19:27-0400

The total electric force is given by formula:

Fnet=Fx2+Fy2(1)F_{net} = \sqrt {{F_{x}}^2+{F_{y}}^2} (1)


Coulomb law

F=k×q1×q2r2(2)F= k×\frac {q_{1}×q_{2}}{r^2} (2)

where k=9×109


Using (2) we get

Fx= 2.4 N (3)

Fy=7.2 N (4)


We put (3) and (4) in (1)

F=7.59 N


tanθ=FyFx(5)\tanθ=\frac {F_{y}}{F_{x}} (5)


We put (3) and (4) in (5)

tanθ=3\tanθ=3

θ=252°

The angle is equal to

360°-252°=108°


Answer

7.59 N

108°


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