Question

A body is given +1C charge. How many electrons added or removed from the body?

Answer 1

We can find how many electrons added or removed from the body from the formula:

$$Q = Ne,$$

here, $Q = +1C$ is the charge of the body, $e = 1.6 \cdot 10^{-19} C$ is the charge of the electron, $N$ is the number of electrons.

Then, we get:

$$N = \dfrac{Q}{e} = \dfrac{1 C}{1.6 \cdot 10^{-19} C} = 6.25 \cdot 10^{18} electrons.$$

Answer:

$N = 6.25 \cdot 10^{18} electrons.$