Answer to Question #90295 in Electricity and Magnetism for zamiir burukude

Question

if the peak current of a.c source is 14A then the rms current to nearest ampere is ..

Answer 1

rms current equals to

$$\frac{14}{2^{0.5}}=\frac{14}{1.41} = 9.9$$

i.e. the nearest ampere is 10 A.