Question #89126

A transverse wave is incident on a boundary separating two media of acoustic impdances Z1 and Z2.
(a) Write down the equations of incident, reflected and transmitted waves. .
(b) Write down the boundary conditions.
(c) Obtain expressions for reflection and
transmission coefficients

Expert's answer

1) For example, consider the following incident wave with incident angle α\alpha, refracted with angle β\beta and transmitted with angle γ\gamma:


pi=p0eik1r=p0exp[ik1(xcos(90α)+ycosα],p_i=p_0e^{ik_1\vec{r}}=p_0\text{exp}[ik_1(x\text{cos}(90^\circ-\alpha)+y\text{cos}\alpha],

reflected wave:


pr=p0Rexp[ik1(xsinβ+ysinβ]p_r=p_0R\text{exp}[ik_1(x\text{sin}\beta+y\text{sin}\beta]

and transmitted wave


pt=p0Dexp[ik2(xsinγ+ycosγ],p_t=p_0D\text{exp}[ik_2(x\text{sin}\gamma+y\text{cos}\gamma],

where k1, k2k_1,\space k_2 - wavenumbers for the mediums.

2) The boundary conditions (y=0):


p0exp(ik1xsinα)+Rp0exp(ik1xsinβ)=Dp0exp(ik2xsinγ).p_0\text{exp}(ik_1x\text{sin}\alpha)+Rp_0\text{exp}(ik_1x\text{sin}\beta)=Dp_0\text{exp}(ik_2x\text{sin}\gamma).

According to Snellius law:


k1sinα=k1sinβ=k2sinγ,k_1\text{sin}\alpha=k_1\text{sin}\beta=k_2\text{sin}\gamma,

then


D=R+1.D=R+1.

The boundary conditions at x=0:


cosαc1ρ1Rcosβc1ρ1=Dcosγc2ρ2.\frac{\text{cos}\alpha}{c_1\rho_1}-R\frac{\text{cos}\beta}{c_1\rho_1}=D\frac{\text{cos}\gamma}{c_2\rho_2}.

3) The reflection and transmission coefficients are


R=Z1Z2Z1+Z2,R=\frac{Z_1-Z_2}{Z_1+Z_2},

D=2Z1Z1+Z2.D=\frac{2Z_1}{Z_1+Z_2}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS