Answer to Question #88963 in Electricity and Magnetism for JAVERIA

Question

a metal strip 6.5cm long,0.88cm wide &0.76mm thick moves with constant velocity v through a magnetic field B=1.2mT perpendicular to the strip.A Potential difference of 3.9V is measured between points x & y across the strip.Calculate the speed V.

Answer 1

$$v= \frac { E_H} { B} = = \frac { \frac { ΔV_H} { w}} { B} (1)$$

where ΔV_H=3.9V, w=0.88×10^-2 m, B=1.2×10^-3 T

Using (1) we got:

v=3.69×10⁵ m/s