Question

Sound waves travelling in a liquid are
incident on a liquid-solid interface. The
impedances of the liquid and the solid are
1.43x 106 Nm-1 s and 3.9 x 107 N m-1 s,
respectively. Calculate the percentage of
sound energy reflected back into the liquid.

Answer 1

The amplitude reflection coefficient is given by formula

$$R=\frac {Z_2-Z_1} { Z_2+Z_1} (1)$$

In our case, Z₁=1.43x 10⁶ Nm^-1 s, Z₂=3.9 x 10⁷ N m^-1 s

Using (1) we got:

R=92.93%

Answer;

92.93%