Question

A metal has Er= 9, Wp=7×10^15 rad s^-115, v=2×10^12 s^-1 . Calculate the skin depth for microwave of 4 cm vacuum wavelength.

Answer 1

The frequency is given by

$$f=\frac {c}{\lambda} (1)$$

where λ=4 cm

Using (1) we got: f=7.5GHz

Skin depth δ is given by formula

$$\delta= \sqrt{\frac {\rho}{\pi f \mu}} (2)$$

where ρ is the resistivity of material, f is the frequency, μ is the permeability

Using (2) we got:

Skin Depth for Copper is equal to 0.7528 μm