Question #87439

At what potential difference must an X-ray tube operate to produce X-rays with a
minimum wavelength of 2A. °

Expert's answer

From the conservation of energy:

eU=hcλeU=\frac{hc}{λ}

U=hceλ=1239.84eVnm(1e)(0.2nm)=6200V=6.2kVU=\frac{hc}{eλ}=\frac{1239.84 eVnm}{(1e)(0.2 nm)}=6200 V=6.2 kV


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