Question

Determine the effective capacitance of the following combination of capacitors given that the capacitance of each capacitor is 3 μF.

Answer 1

And so, the first step

С_eq1 = C₁ + C₂

С_eq1 = 3 μF + 3 μF = 6 μF

The second step

1/C_eq = 1/C_eq1 + 1/C₃

C_eq = (C_eq1 x C₃) / (C_eq1 + C₃)

C_eq = (6 μF x 3 μF) / (6 μF + 3 μF) = 2 μF

Answer: 2 μF