Question

How much work is required to carry a charge of 3X10-5C from a point 50cm from a charge 2X10-4C to a point 20cm from it?

Answer 1

Answer on Question #84920 – Physics – Electromagnetism

Task:

How much work is required to carry a charge of $3*10^{-5}$ C from a point 50cm from a charge $2*10^{-4}$ C to a point 20cm from it?

Solution:

$$W = \Delta E = \frac {k Q _ {1} Q _ {2}}{r _ {1}} - \frac {k Q _ {1} Q _ {2}}{r _ {2}}$$ $$W = \frac {(9 * 1 0 ^ {9} \frac {N * m ^ {2}}{C ^ {2}}) (3 * 1 0 ^ {- 5} \mathrm {C}) * (2 * 1 0 ^ {- 4} \mathrm {C})}{0 . 5 \mathrm {m}} - \frac {(9 * 1 0 ^ {9} \frac {N * m ^ {2}}{C ^ {2}}) (3 * 1 0 ^ {- 5} \mathrm {C}) * (2 * 1 0 ^ {- 4} \mathrm {C})}{0 . 2 \mathrm {m}} =$$ $$= - 1 6 2 N * m = - 1 6 2 J$$ $$W = - 1 6 2 J$$ $$\left| W \right| = 1 6 2 J o u l e$$

**Answer:** 162 Joule.

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