Question

why the electric field for non-conducting charged plane is surface charge density over 2epsulum
while it equal surface charge denisty over epsulm only on conductor case

Answer 1

Answer on Question #82468, Physics / Electromagnetism

**Question:**

why the electric field for non-conducting charged plane is surface charge density over 2epsulum while it equal surface charge density over epsulum only on conductor case

**Solution:**

In accordance with Gauss's theorem an electric field strength of a charged plane equals to

$$E = \frac{\sigma}{2\varepsilon_0}$$

, $\sigma$ - surface charge density. If we regard an electric capacitor we have two different plates with opposite charges, the net electric field strength in this case is the vector sum of electric fields strengths generated by each plate, and this sum equals to

$$E_n = \frac{\sigma}{\varepsilon_0}$$

.

**The answer:**

Please see the explanation above.

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