Question

Find magnitude of charge passing through coil when area is 5*10^3m^2, number of turns is 10, and resistance is 10ohms with its plane at right angles to a uniform magnetic field B = 0.08T

Answer 1

Answer on Question #82350, Physics / Electromagnetism

Question:

Find magnitude of charge passing through coil when area is $5*10^3\mathrm{m}^2$, number of turns is 10, and resistance is 10 ohms with its plane at right angles to a uniform magnetic field $\mathbf{B} = 0.08\mathbf{T}$

Solution:

In accordance with Faraday's law $\mathrm{E} = \frac{d\varPhi}{dt}$ and the current $I = \frac{E}{R}$. Then

$$q = \int I d t = \int \frac {d \Phi}{R d t} d t = \frac {\Delta \Phi}{R} = \frac {B S N}{R}, \text{ respectively } q = \frac {0 . 0 8 \cdot 5 \cdot 1 0 ^ {3} \cdot 1 0}{1 0} = 4 0 0 (C).$$

The answer:

$$q = \frac {B S N}{R} = 4 0 0 C$$

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