Question

2A current is passed along the diameter AB of a circular loop. Find the
magnetic field at the center O of the loop. Radius of the loop is 2cm . pls explain
And what theory should i learn more about it.

Answer 1

Answer on Question #82219 Physics / Electromagnetism

2A current is passed along the diameter AB of a circular loop. Find the magnetic field at the center O of the loop. Radius of the loop is 2cm.

Solution:

We have two semi-circulars. The magnetic field at the center first semi-circular

$$B _ {1} = \frac {\mu_ {0} I _ {1}}{4 r}$$

The magnetic field at the center second semi-circular

$$B _ {2} = \frac {\mu_ {0} I _ {2}}{4 r}$$

Since $I_{1} = I_{2} = 1$ A, we get

$$B _ {1} = B _ {2}$$

The superposition principle states

$$\boldsymbol {B} = \boldsymbol {B} _ {1} + \boldsymbol {B} _ {2}$$

Because the magnetic fields from two semi-circulars have opposite direction, we obtain $B = B_{1} - B_{2} = 0$

For further studying please see

https://en.wikipedia.org/wiki/Biot-Savart_law

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/curloo.#c1

Answer: $B = 0$

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