Question

A 2m long fixed string nodes at both ends when it vibrates in its fundamental mode if the distance between this nodes is 12m.what are nunber of (a) nodes (b)anti-nodes?

Answer 1

Answer on Question #82090, Physics / Electromagnetism

Question:

A 2m long fixed string nodes at both ends when it vibrates in its fundamental mode if the distance between this nodes is 12m. what are number of (a) nodes (b) anti-nodes?

Solution:

The wave length equals $\lambda = 2*2 = 4$ (m), therefore in the second case we have 3 "full waves". The distance between nodes is $\lambda / 4$ , it means there are 7 nodes and 6 anti-nodes.

The answer:

There are 7 nodes and 6 anti-nodes.

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