Question #82002

A current of I Ampere flows in a circular arc of wire which subtends an angle of 3π/2 radians at it's center, whose radius is R. The magnetic induction B at the centre is?

Expert's answer

Answer on Question #82002, Physics / Electromagnetism

**Question:**

A current of I Ampere flows in a circular arc of wire which subtends an angle of 3π/23\pi/2 radians at its center, whose radius is R. The magnetic induction B at the centre is?

**Solution:**

For a circle Bc=μ0I2RB_{c} = \frac{\mu_{0}I}{2R}, respectively for the arc B=μ0I2R×1.5π2π=123.141078R=4.7107RB = \frac{\mu_{0}I}{2R} \times \frac{1.5\pi}{2\pi} = \frac{12 \cdot 3.14 \cdot 10^{-7}}{8R} = \frac{4.7 \cdot 10^{-7}}{R} (T).

**The answer:**


B=4.7107RT.B = \frac{4.7 \cdot 10^{-7}}{R} \text{T}.


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