My orders
How it works
Examples
Reviews
Blog
Homework Answers
Submit
Sign in
How it works
Examples
Reviews
Homework answers
Blog
Contact us
Submit
Question #7990
An electron is trapped in a magnetic field B, & circulating w/ velocity v @ a radius of r. Find an expression for e/m ratio as a function of the frequency of its circular motion.
Expert's answer
F
=
q
B
v
sin
90
∘
=
q
v
B
m
v
2
R
=
e
v
B
≫
m
v
R
=
e
B
≫
R
=
m
v
e
B
T
=
2
π
R
v
=
2
π
m
e
B
≫
v
=
1
T
=
e
B
2
π
m
≫
e
m
=
2
π
v
B
\begin{array}{l} F = q B v \sin 90{}^{\circ} = q v B \\ \frac{m v^{2}}{R} = e v B \gg \frac{m v}{R} = e B \gg R = \frac{m v}{e B} \\ T = \frac{2 \pi R}{v} = \frac{2 \pi m}{e B} \gg v = \frac{1}{T} = \frac{e B}{2 \pi m} \gg \frac{e}{m} = \frac{2 \pi v}{B} \\ \end{array}
F
=
qB
v
sin
90
∘
=
q
v
B
R
m
v
2
=
e
v
B
≫
R
m
v
=
e
B
≫
R
=
e
B
m
v
T
=
v
2
π
R
=
e
B
2
πm
≫
v
=
T
1
=
2
πm
e
B
≫
m
e
=
B
2
π
v
Answer:
e
m
=
2
π
v
B
\frac{e}{m} = \frac{2 \pi v}{B}
m
e
=
B
2
π
v
Our fields of expertise
Programming
Math
Engineering
Economics
Physics
LATEST TUTORIALS
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult. You can find this expert in "Assignmentexpert.com" with confidence. Exceptional experts! I appreciate your help. God bless you!
#340153
on Dec 2023
Read all reviews >>