A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 Tesla . The magnetic field is perpendicular to the length of the wire . The force on the wire is (1) 2.4N (2) 1.2 N (3) 3.0N (4) 2.0N
The Ampere’s force law states
F=BIl sinα
So
F=2×1.2×0.5×sin〖90°=1.2 N〗
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!