Question #71607

Find the magnetizing field H and the magnetic flux density point of B at (a) a 105 mm from a long straight wire carrying a current of 15 A and (b) the center a 2000-turn solenoid which is 0.24m long and bears a current of 1.6A
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Expert's answer

2017-12-07T10:23:06-0500

Answer on Question #71607-Physics-Electromagnetism

Find the magnetizing field HH and the magnetic flux density point of BB at (a) a 105 mm from a long straight wire carrying a current of 15 A and (b) the center a 2000-turn solenoid which is 0.24m long and bears a current of 1.6A

Solution

a)


H=Bμ0=μ0I2πr1μ0=I2πrH = \frac{B}{\mu_0} = \frac{\mu_0 I}{2\pi r} \frac{1}{\mu_0} = \frac{I}{2\pi r}H=152π(0.105)=22.7AmH = \frac{15}{2\pi(0.105)} = 22.7 \frac{A}{m}B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}H=(4π)152π(0.105)107=28.57μTH = \frac{(4\pi)15}{2\pi(0.105)10^7} = 28.57 \, \mu T


b)


H=nIH = nIH=20000.241.6=13.33AmH = \frac{2000}{0.24} \cdot 1.6 = 13.33 \frac{A}{m}B=μ0HB = \mu_0 HB=(4π)20001070.241.6=0.0168TB = \frac{(4\pi) \cdot 2000}{10^7 \cdot 0.24} \cdot 1.6 = 0.0168 \, T


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