Question #69089

A sinusoidal plane electromagnetic wave propagates from water (nw =1.33) to glass
(ng = 1.5). Calculate the reflection and transmission coefficients for this wave at the
interface of the two media. Show that when an electromagnetic wave enters from
one dielectric medium to the other, its frequency remains unchanged.
1

Expert's answer

2017-07-04T10:33:07-0400

Answer on question #69089 – Physics / Electromagnetism

A sinusoidal plane electromagnetic wave propagates from water (nw = 1.33) to glass (ng = 1.5). Calculate the reflection and transmission coefficients for this wave at the interface of the two media. Show that when an electromagnetic wave enters from one dielectric medium to the other, its frequency remains unchanged.

Solution

By definition the reflection and transmission coefficients are


r=n1n2n1+n2,t=2n2n1+n2r = \frac {n _ {1} - n _ {2}}{n _ {1} + n _ {2}}, t = \frac {2 n _ {2}}{n _ {1} + n _ {2}}


Using these formulas we get


r=1.51.331.5+1.33=0.06r = \frac {1.5 - 1.33}{1.5 + 1.33} = 0.06t=21.331.5+1.33=0.94t = \frac {2 * 1.33}{1.5 + 1.33} = 0.94


Let we have two electromagnetic waves from two sides of the interface. Their energies are E1=h2πω1E_{1} = \frac{h}{2\pi}\omega_{1} and E2=h2πω2E_{2} = \frac{h}{2\pi}\omega_{2}. Due to conservation energy law we have E1=E2E_{1} = E_{2}, hence ω1=ω2\omega_{1} = \omega_{2}.

Answer reflection coefficient r=0.06r = 0.06, transmission coefficient t=0.94t = 0.94.

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