Question

A charge of 8.5 x 10^-6 is in an electric field that has a strength of 3.2 x10^5 what is the electric force

Answer 1

Answer on Question 65588, Physics, Electromagnetism

Question:

A charge of $8.5 \cdot 10^{-6} \, C$ is in an electric field that has a strength of $3.2 \cdot 10^{5} \, N / C$. What is the electric force?

Solution:

By the definition of the electric field strength we have:

$$E = \frac {F _ {e}}{q},$$

here, $E$ is the electric field strength, $F_{e}$ is the electric force, $q$ is the charge.

Then, from this formula we can find the electric force:

$$F _ {e} = q E = 8.5 \cdot 10^{-6} \, C \cdot 3.2 \cdot 10^{5} \, \frac {N}{C} = 2.72 \, N.$$

Answer:

$$F _ {e} = 2.72 \, N.$$

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