Answer on Question #62832, Physics / Electromagnetism
A series circuit consisting of an unchanged 42μF capacitor and 10M ohms resistor is connected to 100V power source. What are the current in the circuit and the charge on the capacitor after one time constant?
Solution:
Charge the capacitor
q=Cε(1−e−τt)=Cε(1−e−1)q=42⋅10−6⋅1⋅(1−e−1)=15.6μC
The current in the circuit
I=RU(e−τt)=RU(e−1)I=107100(e−1)=0.37μA
Answer: 0.37μA and 15.6μC
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