Question #61356

17) An ammeter is suspeted of giving inaccurate readings. In order to confirm the readings, the ammeter is connected to a silver votltameter in series and a steady current is passed for one hour. The ammeter reads 0.56A and 2.0124g of silver is deposited. Wha
a) 0.06A
b) 0.11A
c)1.1A
d) 6.0A
18) The magnetic flux through each loop of a 35-loop coil is given by (3:6tÀ0:71t3) 10À2Tm2 , where the time is in seconds. Determine the induced emf at t=5.0s.
a)6.17V
b) 14.43V
c) 17.49V
d) 9.17V

Expert's answer

Answer on Question #61356-Physics-Electromagnetism

17) An ammeter is suspected of giving inaccurate readings. In order to confirm the readings, the ammeter is connected to a silver voltmeter in series and a steady current is passed for one hour. The ammeter reads 0.56A and 2.0124g of silver is deposited. What is the accurate readings of the ammeter?

a) 0.06A

b) 0.11A

c) 1.1A

d) 6.0A

Solution


m=QACv,m = \frac {Q A}{C v},


where mm is the mass of silver, QQ is charge transferred, A=108kgkmolA = 108\frac{kg}{kmol} is atomic weight of silver, C=9.65107CkmolC = 9.65 \cdot 10^{7}\frac{C}{kmol}, vv is valence.


m=QACvm=ltACv2.0124103=I36009.65107(1081)I=0.50A.m = \frac {Q A}{C v} \rightarrow m = \frac {l t A}{C v} \rightarrow 2. 0 1 2 4 \cdot 1 0 ^ {- 3} = \frac {I \cdot 3 6 0 0}{9 . 6 5 \cdot 1 0 ^ {7}} \left(\frac {1 0 8}{1}\right)\rightarrow I = 0. 5 0 A.


Answer: 0.50A.

18) The magnetic flux through each loop of a 35-loop coil is given by (3:6tA0:71t3)A10A2Tm2, where the time is in seconds. Determine the induced emf at t=5.0st = 5.0s.

a) 6.17V

b) 14.43V

c) 17.49V

d) 9.17V

Solution


Φ=(3.6t0.71t3)102.\Phi = (3. 6 t - 0. 7 1 t ^ {3}) 1 0 ^ {- 2}.ε=NdΦdt=35(3.6+3(0.71)t2)102.\varepsilon = - N \frac {d \Phi}{d t} = 3 5 (- 3. 6 + 3 (0. 7 1) t ^ {2}) 1 0 ^ {- 2}.ε(5)=35(3.6+3(0.71)52)102=17.49V.\varepsilon (5) = 3 5 (- 3. 6 + 3 (0. 7 1) 5 ^ {2}) 1 0 ^ {- 2} = 1 7. 4 9 V.


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