Question

a balloon with a charge of 6.0 x 10^-5 C is held at a distance of .10m from a second ballon with the same charge what is the repulsive force and why

Answer 1

Answer on Question 58243, Physics, Electromagnetism

Question:

A balloon with a charge of $6.0 \cdot 10^{-5} \, C$ is held at a distance of $0.10 \, m$ from a second balloon with the same charge. What is the repulsive force and why?

Solution:

We can find the magnitude of the repulsive force from the Coulomb's Law:

$$F_{repulsive} = k \frac{q_1 q_2}{r^2},$$

here, $k = \frac{1}{4\pi\varepsilon_0} = 9 \cdot 10^9 \frac{N \cdot m^2}{C^2}$ is the Coulomb's constant, $q_1 = q_2 = 6.0 \cdot 10^{-5} \, C$ is the charges of two balloons, $r$ is the distance between two balloons.

Then, we get:

$$F_{repulsive} = 9 \cdot 10^9 \frac{N \cdot m^2}{C^2} \cdot \frac{6.0 \cdot 10^{-5} \, C \cdot 6.0 \cdot 10^{-5} \, C}{(0.10 \, m)^2} = 3240 \, N.$$

Answer:

$$F_{repulsive} = 3240 \, N.$$

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