Question #56080

You need to produce a solenoid that has an inductance of 3.67 μH . You construct the solenoid by uniformly winding 1.09 m of thin wire around a tube. How long, in centimeters, should the tube be?
1

Expert's answer

2018-03-31T10:58:52-0400

Answer on Question #56080-Physics-Electromagnetism

You need to produce a solenoid that has an inductance of 3.67 μH3.67\ \mu\mathrm{H}. You construct the solenoid by uniformly winding 1.09 m1.09\ \mathrm{m} of thin wire around a tube. How long, in centimeters, should the tube be?

Solution

L=μ0N2AzL = \frac{\mu_0 N^2 A}{z}N=x2πrr=x2πNN = \frac{x}{2\pi r} \rightarrow r = \frac{x}{2\pi N}A=πr2=πx24π2N2A = \pi r^2 = \frac{\pi x^2}{4\pi^2 N^2}L=μ0N2Az=μ0N2πx24π2N2z=μ0x24πzL = \frac{\mu_0 N^2 A}{z} = \frac{\mu_0 N^2 \pi x^2}{4\pi^2 N^2 z} = \frac{\mu_0 x^2}{4\pi z}z=μ0x24πL=4107(1.09)243.67106=0.032 mz = \frac{\mu_0 x^2}{4\pi L} = \frac{4 \cdot 10^{-7} \cdot (1.09)^2}{4 \cdot 3.67 \cdot 10^{-6}} = 0.032\ \mathrm{m}


Answer: 0.032 m0.032\ \mathrm{m}.


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Comments

Assignment Expert
31.03.18, 17:59

Dear Neil, you are right. Check updated answer.

Neil
31.03.18, 06:43

You lost a pi in the denomenator

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