Question

Two charges
Q1=500μC
and
Q2=100μC
are located on the XY plane at the positions
r1=3j⃗
m and
r2=4i⃗
m. Find the force exerted on the
Q2
14.4i⃗ +10.8j⃗ N
14.4i⃗ –10.8j⃗ N
10.8i⃗ –14.4j⃗ N
10.8i⃗ +14.4j⃗ N

Answer 1

Answer on question #55892, Physics / Electromagnetism

Question Two charges Q1=500C and Q2=100C are located on the XY plane at the positions r1=3j m and r2=4i m. Find the force exerted on the Q2

Solution Total force is

$F=k\,\frac{Q_{1}Q_{2}}{\sqrt{r_{1}^{+}r_{2}}}=9\cdot 10^{9}\frac{500\cdot 10^{-6}\cdot 100\cdot 10^{-6}}{5^{2}}=18\,N$

X-component is

$F\cdot\cos\alpha=18\cdot\frac{4}{5}=14.4$

Y-component is

$F\cdot\sin\alpha=18\cdot\frac{-3}{5}=-10.8$

Hence, answer is 14.4i-10.8j N