Question

A wavelength is 3.50 cm on a region that is upper and another wavelength that is 4.20 cm. If the speed of the waves on the upper portion is 6.90 cm/s, then the speed of the waves on the lower region is?

Answer 1

Answer on Question #43418, Physics, Electrodynamics

A wavelength is $3.50~\mathrm{cm}$ on a region that is upper and another wavelength that is $4.20~\mathrm{cm}$. If the speed of the waves on the upper portion is $6.90~\mathrm{cm/s}$, then the speed of the waves on the lower region is?

Solution:

The mathematical relationship between the speed (v) of a wave and its wavelength ($\lambda$) and frequency (f) is

$$v = f \lambda$$

In our case the frequency is constant, thus

$$f = \frac{v_1}{\lambda_1} = \frac{v_2}{\lambda_2}$$

So,

$$v_2 = v_1 \frac{\lambda_2}{\lambda_1} = 6.9 \cdot \frac{4.20}{3.50} = 8.28~\mathrm{cm/s}$$

Answer: $v_2 = 8.28~\mathrm{cm/s}$

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