A solid cylinder of length L and radius R has a uniform charge density of rho "P". Calculate the electric field vector on the axis of the cylinder, a distance z from the center, and outside the cylinder.
ie: z > L/2
The answer to the question is available in the PDF file https://assignmentexpert.com/https://assignmentexpert.com/homework-answers/physics-answer-42494.pdf
According to [url=https://en.wikipedia.org/wiki/Gauss%27s_law]Gauss
law[/url], one can write 4*\pi*Q = \int E dS. Let us consider a
cylindrical volume of radius r and length l with infinite thin charged
thread on the axis. The total charge in this volume will be Q =
\lambda*l where \lambda is a linear charge density. The surface area
of the given volume is S = 2*\pi*r*l -- only through edge surface of
this cylindrical volume the flux of E is nonzero. So, 4*\pi*\lambda*l
= E * 2*\pi*r*l or E = 2*\lambda/r.
guest
17.05.14, 04:36
how did you get 2 λ / r ?
Leave a comment
Thank you! Your comments have been successfully added. However, they need to be checked by the moderator before being published.
Comments
According to [url=https://en.wikipedia.org/wiki/Gauss%27s_law]Gauss law[/url], one can write 4*\pi*Q = \int E dS. Let us consider a cylindrical volume of radius r and length l with infinite thin charged thread on the axis. The total charge in this volume will be Q = \lambda*l where \lambda is a linear charge density. The surface area of the given volume is S = 2*\pi*r*l -- only through edge surface of this cylindrical volume the flux of E is nonzero. So, 4*\pi*\lambda*l = E * 2*\pi*r*l or E = 2*\lambda/r.
how did you get 2 λ / r ?
Leave a comment