Question

find the radius of the path of 35cl- ions in such a machine if v=3.0kv and b=3.0t

Answer 1

$\frac{mv^2}r=qvB,\implies$

$r=\frac{mv}{qB},$

$\frac{mv^2}2=qU,\implies$

$v=\sqrt\frac{2qU}m,$

$r=\frac m{qB}\sqrt\frac{2qU}{m}=\sqrt\frac{2Um}{qB},$

$r=0.1~mm.$