Question #345786

The current through a circuit, in which emf of a cell ε = 120V and internal


resistance r = 0.01Ω is connected with load R= 1000Ω, is:


Expert's answer

I=εR+r=120 mA.I=\frac{\varepsilon}{R+r}=120~mA.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS