Question #33909

A charged particle is fired into a cubical region of space where there is a uniform magnetic field. Outside this region, there is no magnetic field. Is it possible that the particle will remain inside the cubical region? Explain.
1

Expert's answer

2013-08-15T08:46:46-0400

If charge has V=constV = \text{const} (V-speed) and VV is perpendicular to BB (B magnetic field), then charge will move by circle trajectory


r=VmqBr = \frac{V \cdot m}{q \cdot B}


where VV – speed

m – mass of charge

q – charge

B – magnetic field

If r<a2r < a \cdot \sqrt{2}, (where aa – side of cubical region) than charge won’t come out from the cubical region.

But if charge has VV (V isn’t perpendicular to BB), then charge will move by spiral trajectory.

Charge will come out from the cubical region.


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Comments

Assignment Expert
16.03.16, 15:59

Sear Sanubam, please use panel for submitting new questions

sanubam
16.03.16, 08:12

A charged particle is fired into a cubical region of space where there is a uniform magnetic field. Outside this region, there is no magnetic field. Is it possible that the particle will remain inside the cubical region? Explain.make it simple answer for short answer question type.

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