Question

A charge of 28.0 nC is placed in a uniform electric field

that is directed vertically upward and has a magnitude of

4.00 104 V/m. What work is done by the electric force when

the charge moves (a) 0.450 m to the right; (b) 0.670 m upward;

(c) 2.60 m at an angle of 45.0° downward from the horizontal?

Answer 1

$А=qEr\cos\alpha,$

1.

$\alpha=90°,\\ A=0~J,$

2.

$\alpha=0°,\\ A=750~\mu J,$

3.

$\alpha=-45°,\\ A=-2.06~mJ.$