Question #329555

Two point charges are placed as follows: charge q1 = -1.50 nC is at y = +6.00 m and charge q2 = +3.20 nC is at the origin. What is the total force (magnitude and direction) exerted by these two charges on a negative point charge q3 = -5.00 nC located at (2.00 m, -4.00 m)?





1
Expert's answer
2022-04-19T10:00:47-0400

F=kq3(q1r12q2r22)=5 nN,F=kq_3(\frac{q_1}{r_1^2}-\frac{q_2}{r_2^2})=5~nN,

α=36°.\alpha=36°.


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