Answer to Question #329529 in Electricity and Magnetism for Terdo

Question

A point charge q1 = +2.40 µC is held stationary at the origin. A second point charge

q2 = - 4.30 µC moves from the point x = 0.150 m, y = 0 to the point x = 0.250 m, y = 0.250 m.

How much work is done by the electric force on q2.

Answer 1

$F=\frac{kq_1q_2}{r}=0.34~J.$