Answer to Question #329067 in Electricity and Magnetism for Zetsu

Question #329067

a proton moving horizontally at 3.5x10^4 m/s enters a uniform magnetic field of 0.075 t directed upward at 30°with the horizontal. find the magnitude of the magnetic force acting on the proton

Expert's answer

"F=qvB\\sin\\alpha=0.13\\cdot 10^{-15}~N."

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