Three capacitors of capacitances C1 = 15 μF, C2 = 30 μF, and C3 = 45μF were connected in series to a potential difference V. Find the equivalent capacitance of the three capacitors.
"\\frac 1C=\\frac 1{C_1}+\\frac 1 {C_2}+\\frac 1{C_3},"
"C=8.2~\\mu F."
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