Question

Three capacitors of capacitances C1 = 15 μF, C2 = 30 μF, and C3 = 45μF were connected in series to a potential difference V. Find the equivalent capacitance of the three capacitors.

Answer 1

$\frac 1C=\frac 1{C_1}+\frac 1 {C_2}+\frac 1{C_3},$

$C=8.2~\mu F.$